添加两个对象数组，用两个 JavaScript 数组中现有和重复的成员替换重复的成员
javascriptweb developmentobject oriented programming更新于 2025/9/25 10:20:17
我们有以下对象数组，我们需要将它们合并为一个，删除属性名称有冗余值的对象 −
const first = [{
name: 'Rahul',
age: 23
}, {
name: 'Ramesh',
age: 27
}, {
name: 'Vikram',
age: 35
}, {
name: 'Harsh',
age: 34
}, {
name: 'Vijay',
age: 21
}];
const second = [{
name: 'Vijay',
age: 21
}, {
name: 'Vikky',
age: 20
}, {
name: 'Joy',
age: 26
}, {
name: 'Vijay',
age: 21
}, {
name: 'Harsh',
age: 34
}, ]
我们定义一个函数 CombineArray，将两个要合并的数组作为参数，并返回一个新数组 −
const combineArray = (first, second) => {
const combinedArray = [];
const map = {};
first.forEach(firstEl => {
if(!map[firstEl.name]){
map[firstEl.name] = firstEl;
combinedArray.push(firstEl);
}
});
second.forEach(secondEl => {
if(!map[secondEl.name]){
map[secondEl.name] = secondEl;
combinedArray.push(secondEl);
}
})
return combinedArray;
}
console.log(combineArray(first, second));
此函数不仅确保从第二个数组中删除重复的条目，而且如果第一个数组中存在任何重复的条目，它也会将其删除。
以下是完整的代码 −
示例
const first = [{
name: 'Rahul',
age: 23
}, {
name: 'Ramesh',
age: 27
}, {
name: 'Vikram',
age: 35
}, {
name: 'Harsh',
age: 34
}, {
name: 'Vijay',
age: 21
}];
const second = [{
name: 'Vijay',
age: 21
}, {
name: 'Vikky',
age: 20
}, {
name: 'Joy',
age: 26
}, {
name: 'Vijay',
age: 21
}, {
name: 'Harsh',
age: 34
}, ]
const combineArray = (first, second) => {
const combinedArray = [];
const map = {};
first.forEach(firstEl => {
if(!map[firstEl.name]){
map[firstEl.name] = firstEl;
combinedArray.push(firstEl);
}
});
second.forEach(secondEl => {
if(!map[secondEl.name]){
map[secondEl.name] = secondEl;
combinedArray.push(secondEl);
}
})
return combinedArray;
}
console.log(combineArray(first, second));
输出
控制台输出将是 −
[
{ name: 'Rahul', age: 23 },{ name: 'Ramesh', age: 27 },{ name: 'Vikram', age: 35 },
{ name: 'Harsh', age: 34 },{ name: 'Vijay', age: 21 },{ name: 'Vikky', age: 20 },
{ name: 'Joy', age: 26 }
]
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有用资源
javascript 参考教程 - 该教程包含有关 javascript 的更多信息:https://www.cainiaomax.com/javascript/
