C# 中的复数
csharpprogrammingserver side programming更新于 2025/9/12 13:26:00
要在 C# 中使用和显示复数，您需要检查实数和虚数。
像 7+5i 这样的复数由两部分组成，实部 7 和虚部 5。这里，虚部是 i 的倍数。
要显示完整的数字，请使用 −
public struct Complex
要将两个复数相加，您需要将实部和虚部相加 −
public static Complex operator +(Complex one, Complex two) {
return new Complex(one.real + two.real, one.imaginary + two.imaginary);
}
您可以尝试运行以下代码以在 C# 中处理复数。
示例
using System;
public struct Complex {
public int real;
public int imaginary;
public Complex(int real, int imaginary) {
this.real = real;
this.imaginary = imaginary;
}
public static Complex operator +(Complex one, Complex two) {
return new Complex(one.real + two.real, one.imaginary + two.imaginary);
}
public override string ToString() {
return (String.Format("{0} + {1}i", real, imaginary));
}
}
class Demo {
static void Main() {
Complex val1 = new Complex(7, 1);
Complex val2 = new Complex(2, 6);
// 将两者相加
Complex res = val1 + val2;
Console.WriteLine("First: {0}", val1);
Console.WriteLine("Second: {0}", val2);
// 显示结果
Console.WriteLine("Result (Sum): {0}", res);
Console.ReadLine();
}
}
输出
First: 7 + 1i Second: 2 + 6i Result (Sum): 9 + 7i
