如何在包含员工记录的 MongoDB 文档中仅显示特定薪资的员工姓名?
mongodbdatabasebig data analytics更新于 2026/1/6 17:37:17
要仅显示特定薪资的员工姓名，请在 MongoDB $ 中设置薪资并获取姓名。让我们创建一个包含文档的集合
> db.demo666.insertOne({"EmployeeName":"John","EmployeeSalary":25000});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea1c04824113ea5458c7d0d")
}
> db.demo666.insertOne({"EmployeeName":"Chris","EmployeeSalary":35000});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea1c05524113ea5458c7d0e")
}
> db.demo666.insertOne({"EmployeeName":"David","EmployeeSalary":65000});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea1c06024113ea5458c7d0f")
}
> db.demo666.insertOne({"EmployeeName":"Carol","EmployeeSalary":40000});
{
"acknowledged" : true,
"insertedId" : ObjectId("5ea1c06f24113ea5458c7d10")
}
借助 find() 方法显示集合中的所有文档 −
> db.demo666.find();
这将产生以下输出 −
{ "_id" : ObjectId("5ea1c04824113ea5458c7d0d"), "EmployeeName" : "John", "EmployeeSalary" : 25000 }
{ "_id" : ObjectId("5ea1c05524113ea5458c7d0e"), "EmployeeName" : "Chris", "EmployeeSalary" : 35000 }
{ "_id" : ObjectId("5ea1c06024113ea5458c7d0f"), "EmployeeName" : "David", "EmployeeSalary" : 65000 }
{ "_id" : ObjectId("5ea1c06f24113ea5458c7d10"), "EmployeeName" : "Carol", "EmployeeSalary" : 40000 }
以下查询使用 $ 并获取具有特定薪水的员工姓名 −
> db.demo666.find({"EmployeeSalary":{$in:[35000,40000]}},{_id:0,"EmployeeSalary":0});
这将产生以下输出 −
{ "EmployeeName" : "Chris" }
{ "EmployeeName" : "Carol" }
