C#中获取当前实例的类型
csharpserver side programmingprogramming更新于 2025/5/20 18:07:17
获取当前实例的类型，代码如下 −
示例
using System;
public class Demo {
public static void Main(){
string s = "Demo";
Console.WriteLine("String = " +s);
Console.WriteLine("String Type = " +s.GetType());
}
}
输出
这将产生以下输出 −
String = Demo String Type = System.String
示例
现在让我们看另一个例子 −
using System;
public class Demo {
public static void Main(){
double val1 = 5.5;
int val2 = 10;
short val3 = 2;
Console.WriteLine("Value = " +val1);
Console.WriteLine("Value Type = " +val1.GetType());
Console.WriteLine("Value = " +val2);
Console.WriteLine("Value Type = " +val2.GetType());
Console.WriteLine("Value = " +val3);
Console.WriteLine("Value Type = " +val3.GetType());
}
}
输出
这将产生以下输出 −
Value = 5.5 Value Type = System.Double Value = 10 Value Type = System.Int32 Value = 2 Value Type = System.Int16
