如何在 MySQL 中获取新列中两列之间的差异?
mysqlmysqli database更新于 2024/12/23 14:04:17
让我们首先创建一个表,其中包含要计算新列中的差异的列 −
mysql> create table DemoTable ( Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, LowValue int, HighValue int ); Query OK, 0 rows affected (0.62 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable(LowValue,HighValue) values(100,200); Query OK, 1 row affected (0.19 sec) mysql> insert into DemoTable(LowValue,HighValue) values(300,700); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable(LowValue,HighValue) values(1000,2000); Query OK, 1 row affected (0.13 sec)
以下是使用 select 语句显示表中的所有记录的查询 −
mysql> select *from DemoTable;
这将产生以下输出 −
+----+----------+-----------+ | Id | LowValue | HighValue | +----+----------+-----------+ | 1 | 100 | 200 | | 2 | 300 | 700 | | 3 | 1000 | 2000 | +----+----------+-----------+ 3 rows in set (0.00 sec)
以下查询用于获取两列之间的差异 −
mysql> select tbl.Id,tbl.LowValue,tbl.HighValue, HighValue-LowValue AS DifferenceBetweenTwoColumns from DemoTable tbl;
这将产生以下输出 −
+----+----------+-----------+-----------------------------+ | Id | LowValue | HighValue | DifferenceBetweenTwoColumns | +----+----------+-----------+-----------------------------+ | 1 | 100 | 200 | 100 | | 2 | 300 | 700 | 400 | | 3 | 1000 | 2000 | 1000 | +----+----------+-----------+-----------------------------+ 3 rows in set (0.00 sec)
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mysql 参考教程 - 该教程包含有关 mysql 的更多信息:https://www.cainiaomax.com/mysql/

