如何从包含员工工资记录的 MySQL 表中获取前 3 名工资?
mysqlmysqli database更新于 2025/11/4 22:04:17
为此，请使用 LIMIT 和 OFFSET。让我们首先创建一个表 −
mysql> create table DemoTable867(EmployeeSalary int); Query OK, 0 rows affected (0.64 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable867 values(63737); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable867 values(899833); Query OK, 1 row affected (0.10 sec) mysql> insert into DemoTable867 values(23644); Query OK, 1 row affected (0.20 sec) mysql> insert into DemoTable867 values(89393); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable867 values(534333); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable867 values(889322); Query OK, 1 row affected (0.08 sec)
使用 select 语句显示表中的所有记录 −
mysql> select *from DemoTable867;
这将产生以下输出 −
+----------------+ | EmployeeSalary | +----------------+ | 63737 | | 899833 | | 23644 | | 89393 | | 534333 | | 889322 | +----------------+ 6 rows in set (0.00 sec)
这是获取第一高工资的查询 −
mysql> select distinct(EmployeeSalary) from DemoTable867 order by EmployeeSalary DESC LIMIT 1;
这将产生以下输出 −
+----------------+ | EmployeeSalary | +----------------+ | 899833 | +----------------+ 1 row in set (0.02 sec)
这是获取第二高薪水的查询 −
mysql> select distinct(EmployeeSalary) from DemoTable867 order by EmployeeSalary DESC LIMIT 1 OFFSET 1;
这将产生以下输出 −
+----------------+ | EmployeeSalary | +----------------+ | 889322 | +----------------+ 1 row in set (0.00 sec)
以下是获取第三高薪水的查询 −
mysql> select distinct(EmployeeSalary) from DemoTable867 order by EmployeeSalary DESC LIMIT 1 OFFSET 2;
这将产生以下输出 −
+----------------+ | EmployeeSalary | +----------------+ | 534333 | +----------------+ 1 row in set (0.00 sec)
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