如何在 MySQL 中按类似排序?
mysqlmysqli database更新于 2025/4/22 13:32:17
要在 MySQL 中按类似排序，请使用 case 语句。语法如下 −
SELECT *FROM yourTableName ORDER BY CASE WHEN yourColumnName like '%yourPatternValue1%' then 1 WHEN yourColumnName like '%yourPatternValue2%' then 2 else 3 end;
为了理解上述语法，让我们创建一个表。创建表的查询如下 −
mysql> create table OrderByLikeDemo -> ( -> Id int, -> Name varchar(100) -> ); Query OK, 0 rows affected (1.84 sec)
使用 insert 命令在表中插入一些记录。 查询语句如下 −
mysql> insert into OrderByLikeDemo values(100,'John Smith'); Query OK, 1 row affected (0.18 sec) mysql> insert into OrderByLikeDemo values(101,'Carol Taylor'); Query OK, 1 row affected (0.23 sec) mysql> insert into OrderByLikeDemo values(102,'David Miller'); Query OK, 1 row affected (0.12 sec) mysql> insert into OrderByLikeDemo values(103,'Mike Taylor'); Query OK, 1 row affected (0.18 sec) mysql> insert into OrderByLikeDemo values(104,'Bob Miller'); Query OK, 1 row affected (0.11 sec) mysql> insert into OrderByLikeDemo values(105,'Sam Williams'); Query OK, 1 row affected (0.16 sec)
使用 select 语句显示表中的所有记录。查询如下 −
mysql> select *from OrderByLikeDemo;
以下是输出 −
+------+--------------+ | Id | Name | +------+--------------+ | 100 | John Smith | | 101 | Carol Taylor | | 102 | David Miller | | 103 | Mike Taylor | | 104 | Bob Miller | | 105 | Sam Williams | +------+--------------+ 6 rows in set (0.00 sec)
以下查询用于获取所有按 ORDER BY 排序的记录，例如 −
mysql> select *from OrderByLikeDemo -> order by case -> when Name like '%Taylor%' then 1 -> when Name like '%Miller%' then 2 -> else 3 -> end;
以下是输出 −
+------+--------------+ | Id | Name | +------+--------------+ | 101 | Carol Taylor | | 103 | Mike Taylor | | 102 | David Miller | | 104 | Bob Miller | | 100 | John Smith | | 105 | Sam Williams | +------+--------------+ 6 rows in set (0.00 sec)
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