如何使用 ORDER BY 在 MySQL 中对同名学生的分数进行求和?

mysqlmysqli database更新于 2025/5/24 13:00:17

为此,请使用 ORDER BY 和 GROUP BY 子句。让我们首先创建一个包含学生姓名和分数的表 −

mysql> create table countRowValueDemo
   -> (
   -> StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   -> StudentName varchar(20),
   -> StudentMathScore int
   -> );
Query OK, 0 rows affected (0.71 sec)

下面是使用 insert 命令向表中插入记录的查询 −

mysql> insert into countRowValueDemo(StudentName,StudentMathScore) values('Larry',45);
Query OK, 1 row affected (0.19 sec)

mysql> insert into countRowValueDemo(StudentName,StudentMathScore) values('Mike',56);
Query OK, 1 row affected (0.16 sec)

mysql> insert into countRowValueDemo(StudentName,StudentMathScore) values('John',60);
Query OK, 1 row affected (0.15 sec)

mysql> insert into countRowValueDemo(StudentName,StudentMathScore) values('David',40);
Query OK, 1 row affected (0.24 sec)

mysql> insert into countRowValueDemo(StudentName,StudentMathScore) values('David',70);
Query OK, 1 row affected (0.12 sec)

mysql> insert into countRowValueDemo(StudentName,StudentMathScore) values('John',80);
Query OK, 1 row affected (0.13 sec)

mysql> insert into countRowValueDemo(StudentName,StudentMathScore) values('David',88);
Query OK, 1 row affected (0.17 sec)

以下是使用 select 语句显示表中的所有记录的查询 −

mysql> select * from countRowValueDemo;

这将产生以下输出 −

+-----------+-------------+------------------+
| StudentId | StudentName | StudentMathScore |
+-----------+-------------+------------------+
| 1         | Larry       | 45               |
| 2         | Mike        | 56               |
| 3         | John        | 60               |
| 4         | David       | 40               |
| 5         | David       | 70               |
| 6         | John        | 80               |
| 7         | David       | 88               |
+-----------+-------------+------------------+
7 rows in set (0.00 sec)

案例 1:降序(求和)

以下查询用于对姓名相似的学生的分数求和。结果将按降序显示 −

mysql> select StudentName,
   -> sum(StudentMathScore) AS TOTAL_SCORE
   -> from countRowValueDemo
   -> group by StudentName
   -> order by sum(StudentMathScore) desc;

这将产生以下输出 −

+-------------+-------------+
| StudentName | TOTAL_SCORE |
+-------------+-------------+
| David       | 198         |
| John        | 140         |
| Mike        | 56          |
| Larry       | 45          |
+-------------+-------------+
4 rows in set (0.00 sec)

案例 2: 升序(求和)

以下查询用于对姓名相似的学生的分数求和。结果将按降序显示 −

mysql> select StudentName,
   -> sum(StudentMathScore) AS TOTAL_SCORE
   -> from countRowValueDemo
   -> group by StudentName
   -> order by sum(StudentMathScore);

这将产生以下输出 −

+-------------+-------------+
| StudentName | TOTAL_SCORE |
+-------------+-------------+
| Larry       | 45          |
| Mike        | 56          |
| John        | 140         |
| David       | 198         |
+-------------+-------------+
4 rows in set (0.00 sec)

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