在 MySQL 中，有没有办法选择部分匹配的值?
mysqlmysqli database更新于 2025/11/2 13:00:17
要部分匹配，请使用 LIKE 运算符。让我们首先创建一个表 −
mysql> create table DemoTable806( StudentId int NOT NULL AUTO_INCREMENT PRIMARY KEY, StudentName varchar(100), StudentSubject varchar(100) ); Query OK, 0 rows affected (0.57 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable806(StudentName,StudentSubject) values('Chris','Java in Depth With Data Structure');
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable806(StudentName,StudentSubject) values('Robert','Introduction to MySQL');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable806(StudentName,StudentSubject) values('Bob','C++ in Depth With Data Structure And Algorithm');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable806(StudentName,StudentSubject) values('Adam','Introduction to MongoDB');
Query OK, 1 row affected (0.11 sec)
使用 select 语句显示表中的所有记录 −
mysql> select *from DemoTable806;
这将产生以下输出 −
+-----------+-------------+------------------------------------------------+ | StudentId | StudentName | StudentSubject | +-----------+-------------+------------------------------------------------+ | 1 | Chris | Java in Depth With Data Structure | | 2 | Robert | Introduction to MySQL | | 3 | Bob | C++ in Depth With Data Structure And Algorithm | | 4 | Adam | Introduction to MongoDB | +-----------+-------------+------------------------------------------------+ 4 rows in set (0.00 sec)
以下是选择部分匹配的值的查询 −
mysql> select *from DemoTable806 where StudentSubject LIKE '%Depth%';
这将产生以下输出 −
+-----------+-------------+------------------------------------------------+ | StudentId | StudentName | StudentSubject | +-----------+-------------+------------------------------------------------+ | 1 | Chris | Java in Depth With Data Structure | | 3 | Bob | C++ in Depth With Data Structure And Algorithm | +-----------+-------------+------------------------------------------------+ 2 rows in set (0.00 sec)
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