C# 中的 Math.Round() 方法
csharpserver side programmingprogramming更新于 2025/8/13 4:52:17
C# 中的 Math.Round() 方法可将值四舍五入为最接近的整数或指定的小数位数。
方法
以下是 Math.Round() 重载的方法 −
Math.Round(Double) Math.Round(Double, Int32) Math.Round(Double, Int32, MidpointRounding) Math.Round(Double, MidpointRounding) Math.Round(Decimal) Math.Round(Decimal, Int32) Math.Round(Decimal, Int32, MidpointRounding) Math.Round(Decimal, MidpointRounding)
示例
现在让我们看一个实现 Math.Round() 方法的示例，即 Math.Round(Decimal) −
using System;
public class Demo {
public static void Main(){
Decimal val1 = 78.12m;
Decimal val2 = 30.675m;
Console.WriteLine("Decimal Value = " + val1);
Console.WriteLine("Rounded value = " + Math.Round(val1));
Console.WriteLine("Decimal Value = " + val2);
Console.WriteLine("Rounded value = " + Math.Round(val2));
}
}
输出
这将产生以下输出 −
Decimal Value = 78.12 Rounded value = 78 Decimal Value = 30.675 Rounded value = 31
示例
让我们看另一个实现 Math.Round() 方法的示例，即 Math.Round(Double) −
using System;
public class Demo {
public static void Main(){
Double val1 = 23.10;
Double val2 = 90.98;
Console.WriteLine("Double Value = " + val1);
Console.WriteLine("Rounded value = " + Math.Round(val1));
Console.WriteLine("Double Value = " + val2);
Console.WriteLine("Rounded value = " + Math.Round(val2));
}
}
输出
这将产生以下输出 −
Double Value = 23.1 Rounded value = 23 Double Value = 90.98 Rounded value = 91
