MySQL 查询用目录链接替换列中最后一个 / 后面的字符串?

mysqlmysqli database更新于 2025/9/14 5:00:17

为此,请使用 substring_index() 方法。让我们首先创建一个表 −

mysql> create table DemoTable
   -> (
   -> FolderName varchar(100),
   -> FolderLocation varchar(200)
   -> );
Query OK, 0 rows affected (1.03 sec)

使用 insert 命令在表中插入一些记录 −

mysql> insert into DemoTable values('CProgram','C:/AllPrograms/.....');
Query OK, 1 row affected (0.13 sec)

mysql> insert into DemoTable values('Images','E:/MyImage/home/garbage');
Query OK, 1 row affected (0.15 sec)

使用 select 语句显示表中的所有记录 −

mysql> select *from DemoTable;

输出

+------------+-------------------------+
| FolderName | FolderLocation          |
+------------+-------------------------+
| CProgram   | C:/AllPrograms/.....    |
| Images     | E:/MyImage/home/garbage |
+------------+-------------------------+
2 rows in set (0.00 sec)

以下查询用于用目录链接替换列中最后一个 / 后面的字符串 −

mysql> UPDATE DemoTable SET FolderLocation = CONCAT(LEFT(FolderLocation , CHAR_LENGTH(FolderLocation ) - CHAR_LENGTH(SUBSTRING_INDEX(FolderLocation , '/', -1))),FolderName);
Query OK, 2 rows affected (0.16 sec)
Rows matched: 2  Changed: 2 Warnings: 0

让我们再次检查表记录 −

mysql> select *from DemoTable;

输出

+------------+-------------------------+
| FolderName | FolderLocation          |
+------------+-------------------------+
| CProgram   | C:/AllPrograms/CProgram |
| Images     | E:/MyImage/home/Images  |
+------------+-------------------------+
2 rows in set (0.00 sec)

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