Python – 元素的分组连续范围索引

pythonserver side programmingprogramming更新于 2025/10/23 1:48:17

当需要获取列表中元素的分组连续范围索引时，将创建一个 defaultdict。使用简单的迭代以及 ‘groupby’ 方法、‘len’ 方法、‘list’ 方法和 ‘append’ 方法。

示例

下面是相同的演示 −

from itertools import groupby
from collections import defaultdict

my_list = [63, 12, 84, 91, 52, 39, 25, 27, 20, 11, 0,9]

print("列表为: " )
print(my_list)

my_index = 0
my_result = defaultdict(list)

for key, sub in groupby(my_list):
   element = len(list(sub))
   my_result[key].append((my_index, my_index + element - 1))
   my_index += element

print("结果字典为:")
print(my_result)

输出

列表为:
[63, 12, 84, 91, 52, 39, 25, 27, 20, 11, 0, 9]
结果字典为:
defaultdict(, {63: [(0, 0)], 12: [(1, 1)], 84: [(2, 2)], 91: [(3, 3)], 52: [(4, 4)], 39: [(5, 5)], 25:
[(6, 6)], 27: [(7, 7)], 20: [(8, 8)], 11: [(9, 9)], 0: [(10, 10)], 9: [(11, 11)]})