在 C# 中将 64 位有符号整数重新解释为双精度浮点数
csharpserver side programmingprogramming更新于 2025/8/31 7:52:17
要将指定的 64 位有符号整数重新解释为双精度浮点数，代码如下 −
示例
using System;
public class Demo {
public static void Main() {
long d = 9846587687;
Console.Write("Value (64-bit signed integer) = "+d);
double res = BitConverter.Int64BitsToDouble(d);
Console.Write("
Value (double-precision floating point number) = "+res);
}
}
输出
这将产生以下输出 −
Value (64-bit signed integer) = 9846587687 Value (double-precision floating point number) = 4.86486070491012E-314
示例
让我们看另一个例子 −
using System;
public class Demo {
public static void Main() {
long d = 20;
Console.Write("Value (64-bit signed integer) = "+d);
double res = BitConverter.Int64BitsToDouble(d);
Console.Write("
Value (double-precision floating point number) = "+res);
}
}
输出
这将产生以下输出 −
Value (64-bit signed integer) = 20 Value (double-precision floating point number) = 9.88131291682493E-323
