从 MySQL 表中选择行并使用 IN() 显示
mysqlmysqli database更新于 2025/11/7 22:04:17
首先我们创建一个表 −
mysql> create table DemoTable778 ( ClientId varchar(100), ClientName varchar(100) ); Query OK, 0 rows affected (1.05 sec)
使用 insert 命令在表中插入一些记录 −
mysql> insert into DemoTable778 values('J-101','John');
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable778 values('A-102','Adam');
Query OK, 1 row affected (0.23 sec)
mysql> insert into DemoTable778 values('C-103','Chris');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable778 values('D-104','David');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable778 values('R-105','Robert');
Query OK, 1 row affected (0.41 sec)
使用 select 语句显示表中的所有记录 −
mysql> select *from DemoTable778;
这将产生以下输出 -
+----------+------------+ | ClientId | ClientName | +----------+------------+ | J-101 | John | | A-102 | Adam | | C-103 | Chris | | D-104 | David | | R-105 | Robert | +----------+------------+ 5 rows in set (0.00 sec)
从 MySQL 表中选择行并使用 IN() 显示 −
mysql> select *from DemoTable778 where ClientId IN('J-101','A-102','C-103','D-104','R-105');
这将产生以下输出 -
+----------+------------+ | ClientId | ClientName | +----------+------------+ | J-101 | John | | A-102 | Adam | | C-103 | Chris | | D-104 | David | | R-105 | Robert | +----------+------------+ 5 rows in set (0.00 sec)
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mysql 参考教程 - 该教程包含有关 mysql 的更多信息:https://www.cainiaomax.com/mysql/

