从 MySQL 表中选择行并使用 IN() 显示

mysqlmysqli database更新于 2025/11/7 22:04:17

首先我们创建一个表 −

mysql> create table DemoTable778 (
   ClientId varchar(100),
   ClientName varchar(100)
);
Query OK, 0 rows affected (1.05 sec)

使用 insert 命令在表中插入一些记录 −

mysql> insert into DemoTable778 values('J-101','John');
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable778 values('A-102','Adam');
Query OK, 1 row affected (0.23 sec)
mysql> insert into DemoTable778 values('C-103','Chris');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable778 values('D-104','David');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable778 values('R-105','Robert');
Query OK, 1 row affected (0.41 sec)

使用 select 语句显示表中的所有记录 −

mysql> select *from DemoTable778;

这将产生以下输出 -

+----------+------------+
| ClientId | ClientName |
+----------+------------+
| J-101    | John       |
| A-102    | Adam       |
| C-103    | Chris      |
| D-104    | David      |
| R-105    | Robert     |
+----------+------------+
5 rows in set (0.00 sec)

从 MySQL 表中选择行并使用 IN() 显示 −

mysql> select *from DemoTable778 where ClientId IN('J-101','A-102','C-103','D-104','R-105');

这将产生以下输出 -

+----------+------------+
| ClientId | ClientName |
+----------+------------+
| J-101    | John       |
| A-102    | Adam       |
| C-103    | Chris      |
| D-104    | David      |
| R-105    | Robert     |
+----------+------------+
5 rows in set (0.00 sec)

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