根据月份从 MySQL 表中选择总计
mysqlmysqli database更新于 2025/8/10 23:08:17
为此，您可以使用 GROUP BY MONTH()。让我们首先创建一个表 −
mysql> create table DemoTable1628 -> ( -> PurchaseDate date, -> Amount int -> ); Query OK, 0 rows affected (1.55 sec)
使用 insert 命令在表中插入一些记录。
mysql> insert into DemoTable1628 values('2019-01-10',1500);
Query OK, 1 row affected (0.68 sec)
mysql> insert into DemoTable1628 values('2019-10-10',2000);
Query OK, 1 row affected (0.61 sec)
mysql> insert into DemoTable1628 values('2019-10-24',100);
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable1628 values('2019-11-10',500);
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable1628 values('2019-12-10',1600);
Query OK, 1 row affected (0.32 sec)
mysql> insert into DemoTable1628 values('2019-10-10',900);
Query OK, 1 row affected (0.47 sec)
使用 select 语句显示表中的所有记录 −
mysql> select * from DemoTable1628;
这将产生以下输出 −
+--------------+--------+ | PurchaseDate | Amount | +--------------+--------+ | 2019-01-10 | 1500 | | 2019-10-10 | 2000 | | 2019-10-24 | 100 | | 2019-11-10 | 500 | | 2019-12-10 | 1600 | | 2019-10-10 | 900 | +--------------+--------+ 6 rows in set (0.00 sec)
以下查询用于根据月份从数据库表中获取总数 −
mysql> select month(PurchaseDate) as Month,year(PurchaseDate) as Year,SUM(Amount) -> from DemoTable1628 -> group by month(PurchaseDate);
这将产生以下输出 −
+-------+------+-------------+ | Month | Year | SUM(Amount) | +-------+------+-------------+ | 1 | 2019 | 1500 | | 10 | 2019 | 3000 | | 11 | 2019 | 500 | | 12 | 2019 | 1600 | +-------+------+-------------+ 4 rows in set (0.20 sec)
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