C# 中两个 HashSet 的并集
csharpserver side programmingprogramming更新于 2025/9/20 14:37:17
我们来看一个获取两个 HashSet 并集的示例
示例
using System;
using System.Collections.Generic;
public class Demo {
public static void Main(){
HashSet<int> set1 = new HashSet<int>();
set1.Add(100);
set1.Add(200);
set1.Add(300);
set1.Add(400);
set1.Add(500);
set1.Add(600);
Console.WriteLine("HashSet1 elements...");
foreach(int ele in set1){
Console.WriteLine(ele);
}
HashSet<int> set2 = new HashSet<int>();
set2.Add(100);
set2.Add(200);
set2.Add(300);
set2.Add(400);
set2.Add(500);
set2.Add(600);
Console.WriteLine("HashSet2 elements...");
foreach(int ele in set2){
Console.WriteLine(ele);
}
Console.WriteLine("Union...");
set1.UnionWith(set2);
foreach(int ele in set1){
Console.WriteLine(ele);
}
}
}
输出
这将产生以下输出 −
HashSet1 elements... 100 200 300 400 500 600 HashSet2 elements... 100 200 300 400 500 600 Union... 100 200 300 400 500 600
示例
现在让我们看另一个例子 −
using System;
using System.Collections.Generic;
public class Demo {
public static void Main(){
HashSet<int> set1 = new HashSet<int>();
set1.Add(100);
set1.Add(200);
set1.Add(300);
set1.Add(400);
set1.Add(500);
set1.Add(600);
Console.WriteLine("HashSet1 elements...");
foreach(int ele in set1){
Console.WriteLine(ele);
}
HashSet<int> set2 = new HashSet<int>();
set2.Add(100);
set2.Add(250);
set2.Add(300);
Console.WriteLine("HashSet2 elements...");
foreach(int ele in set2){
Console.WriteLine(ele);
}
Console.WriteLine("Union...");
set1.UnionWith(set2);
foreach(int ele in set1){
Console.WriteLine(ele);
}
}
}
输出
这将产生以下输出 −
HashSet1 elements... 100 200 300 400 500 600 HashSet2 elements... 100 250 300 Union... 100 200 300 400 500 600 250
