C 语言中的字符串字谜程序

更新于 2025/3/16 11:22:17

实施

现在，我们将看到程序的实际实施 −

#include <stdio.h>
#include <string.h>

int main (void) {
   char s1[] = "recitals";
   char s2[] = "articles";

   char temp;

   int i, j;
   int n  = strlen(s1);
   int n1 = strlen(s2);

   // 如果两个字符串的长度不同，那么它们就不是字谜

   if( n != n1) {    
      printf("%s and %s are not anagrams! 
", s1, s2);
      return 0;
   }
   
   // 首先对两个字符串进行排序 −

   for (i = 0; i < n-1; i++) {
      for (j = i+1; j < n; j++) {
         if (s1[i] > s1[j]) {
            temp  = s1[i];
            s1[i] = s1[j];
            s1[j] = temp;
         }
         if (s2[i] > s2[j]) {
            temp  = s2[i];
            s2[i] = s2[j];
            s2[j] = temp;
         }
      }
   }

   // 逐个字符地比较两个字符串

   for(i = 0; i<n; i++) {
      if(s1[i] != s2[i]) {    
         printf("Strings are not anagrams! 
", s1, s2);
         return 0;
      }
   }

   printf("Strings are anagrams! 
");
   return 0;
}