如何在 Java 中从数组中查找公共元素

问题描述

如何从数组中查找公共元素?

解决方案

以下示例显示如何从两个数组中查找公共元素并将它们存储在一个数组中。

import java.util.ArrayList;

public class NewClass {
   public static void main(String[] args) {
      ArrayList objArray = new ArrayList();
      ArrayList objArray2 = new ArrayList();
      objArray2.add(0,"common1");
      objArray2.add(1,"common2");
      objArray2.add(2,"notcommon");
      objArray2.add(3,"notcommon1");
      objArray.add(0,"common1");
      objArray.add(1,"common2");
      objArray.add(2,"notcommon2");
      System.out.println("Array elements of array1"+objArray);
      System.out.println("Array elements of array2"+objArray2);
      objArray.retainAll(objArray2);
      System.out.println("Array1 after retaining common elements of array2 & array1"+objArray);
   }
}

结果

上述代码示例将产生以下结果。

Array elements of array1[common1, common2, notcommon2]
Array elements of array2[common1, common2, notcommon,
notcommon1]
Array1 after retaining common elements of array2 & array1
[common1, common2]

另一个从数组中查找公共元素的示例

public class HelloWorld {
   public static void main(String a[]) {
      int[] arr1 = {4,7,3,9,2};
      int[] arr2 = {3,2,12,9,40,32,4};
      
      for(int i = 0;i < arr1.length; i++) {
         for(int j = 0; j < arr2.length; j++) {
            if(arr1[i] == arr2[j]) { 
               System.out.println(arr1[i]);
            } 
         } 
      }
   }
}

上述代码示例将产生以下结果。

4 
3 
9 
2