如何在 Java 中处理多个异常(除以零)

问题描述

如何使用处理多个异常(除以零)?

解决方案

此示例显示如何在除以零时处理多个异常?

public class Main {
   public static void main (String args[]) {
      int array[] = {20,20,40};
      int num1 = 15, num2 = 0;
      int result = 0;
      try {
         result = num1/num2;
         System.out.println("The result is" +result);
         
         for(int i = 2; i >= 0; i--) {
            System.out.println("The value of array is" +array[i]);
         }
      } catch (ArrayIndexOutOfBoundsException e) {
         System.out.println("Error. Array is out of Bounds"+e);
      } catch (ArithmeticException e) {
         System.out.println ("Can't be divided by Zero"+e);
      }
   }
}

结果

上述代码示例将产生以下结果。

Can't be divided by Zerojava.lang.ArithmeticException: / by zero

以下是另一个使用 Java 处理多个异常的示例。

public class JavaApplication4 { 
   public static void main(String args[]) { 
      try { 
         int a[] = new int[5];
         a[5] = 30/0;  
      }  
      catch(ArithmeticException e){System.out.println("task1 is completed");}  
      catch(ArrayIndexOutOfBoundsException e){System.out.println("task 2 completed");}  
      catch(Exception e){System.out.println("common task completed");}
      System.out.println("rest of the code...");  
   }  
} 

上述代码示例将产生以下结果。

task1 is completed
rest of the code...