Python - 根据列表中第 K 个键的值过滤字典

pythonserver side programmingprogramming更新于 2025/10/29 7:08:17

当需要根据列表中第"K"个键的值过滤字典时，可以使用指定条件的简单迭代。

示例

下面是相同的演示

my_list = [{"Python": 2, "is": 4, "cool": 11},
   {"Python": 5, "is": 1, "cool": 1},
   {"Python": 7, "is": 3, "cool": 7},
   {"Python": 9, "is": 9, "cool": 8},
   {"Python": 4, "is": 10, "cool": 6}]

print("列表为:")
print(my_list)

search_list = [1, 9, 8, 4, 5]

key = "is"

my_result = []

for sub in my_list:
   if sub[key] in search_list:
      my_result.append(sub)

print("结果为:")
print(my_result)

输出

列表为:
[{'Python': 2, 'is': 4, 'cool': 11}, {'Python': 5, 'is': 1, 'cool': 1}, {'Python': 7, 'is': 3, 'cool': 7}, {'Python': 9, 'is': 9, 'cool': 8}, {'Python': 4, 'is': 10, 'cool': 6}]
结果为:
[{'Python': 2, 'is': 4, 'cool': 11}, {'Python': 5, 'is': 1, 'cool': 1}, {'Python': 9, 'is': 9, 'cool': 8}]