Python 程序从列表中获取所有成对组合

pythonserver side programmingprogramming更新于 2025/10/29 6:36:17

当需要从列表中获取所有成对组合时，会使用迭代和‘append’方法。

示例

下面是相同的演示

my_list = [15,"John", 2, "Will", 53, 'Rob']

print("列表为:")
print(my_list)

my_result = []

for i in range(0,len(my_list)):
   for j in range(0,len(my_list)):

      if (i!=j):
         my_result.append((my_list[i],my_list[j]))

print("结果为:")
print(my_result)

输出

列表为:
[15, 'John', 2, 'Will', 53, 'Rob']
结果为:
[(15, 'John'), (15, 2), (15, 'Will'), (15, 53), (15, 'Rob'), ('John', 15), ('John', 2), ('John', 'Will'), ('John', 53), ('John', 'Rob'), (2, 15), (2, 'John'), (2, 'Will'), (2, 53), (2, 'Rob'), ('Will', 15), ('Will', 'John'), ('Will', 2), ('Will', 53), ('Will', 'Rob'), (53, 15), (53, 'John'), (53, 2), (53, 'Will'), (53, 'Rob'), ('Rob', 15), ('Rob', 'John'), ('Rob', 2), ('Rob', 'Will'), ('Rob', 53)]