用于从字符串中删除第 n 个字符的 Python 程序?
programmingpythonserver side programming更新于 2025/3/14 13:32:17
在本文中,我们将从 Python 中的字符串中删除第 n 个字符。假设我们有以下输入字符串 -
Amitdiwan
删除第 n 个字符(即第 2 个索引)后,输出应如下所示 -
Amt
用于从字符串中删除第 n 个字符的 Python 程序
在此示例中,我们将从字符串中删除第 n 个字符 -
示例
def removechar(str1, n): x = str1[ : n] y = str1[n + 1: ] return x + y # Driver Code if __name__ == '__main__': str1 = input("Enter a String =") n = int(input("Enter the n-th index =")) print("The new string =\n") print(removechar(str1, n))
输出
Enter a String= Jacob Enter the n-th index = 2 The new string = Jaob
无需用户输入即可从字符串中删除第 n 个字符的 Python 程序
在此示例中,我们将无需用户输入即可从字符串中删除第 n 个字符 −
示例
def removechar(myStr, n): x = myStr[ : n] y = myStr[n + 1: ] return x + y # Driver Code if __name__ == '__main__': myStr = "Hello" print("String = ",myStr) # nth index # character to be removed at this index n = 2 print("The new string = ",removechar(myStr, n))
输出
String = Hello The new string = Helo
使用 for 循环从字符串中删除第 n 个字符的 Python 程序
在此示例中,我们将使用 for 循环从字符串中删除第 n 个字符 −
示例
# Create a String myStr = "How are you?" # Display the initial string print("String = ",myStr) # nth index # The character is to be removed at this index n = 9 newStr = '' # for loop iteration for char in range(0, len(myStr)): if(char != n): # append newStr += myStr[char] # Display the updated string print("Updated string = ",newStr)
输出
String = How are you? Updated string = How are yu?
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有用资源
python 参考教程 - 该教程包含有关 python 的更多信息:https://www.cainiaomax.com/python/

