C++ algorithm any_of() 函数

示例

判断向量中是否存在大于 5 的数字：

bool greater_than_5 (int value) {
  return value > 5;
}

int main() {
  vector<int> numbers = {1, 7, 3, 5, 9, 2};
  if (any_of(numbers.begin(), numbers.end(), greater_than_5)) {
    cout << "Found a value greater than 5";
  } else {
    cout << "No values are greater than 5";
  }
  
  return 0;
}