C++ algorithm find_if_not() 函数

示例

在向量中找出不大于 5 的值：

bool greater_than_5(int value) {
  return value > 5;
}

int main() {
  vector<int> numbers = {1, 7, 3, 5, 9, 2};
  auto it = find_if_not(numbers.begin(), numbers.end(), greater_than_5);
  if (it != numbers.end()) {
    cout << "The number " << *it << " is not greater than 5.";
  } else {
    cout << "All numbers are greater than 5.";
  }
  
  return 0;
}